Calculated acos({a}) = NAN? {=acos({a})}

log({b}) = -INF? {=log({b})}

1/{b} = INF? {=1.0/{b}}

]]> 1.0000000 0.3333333 0 0 0 abc 1 acos({a}) 0.1 1 2 2 log({b}) 0.1 1 2 2 1.0/{b} 0.1 1 2 2 0 0.1000000 3 0 private a calculated uniform 1 2 1 1 1 1.1 1 private b calculated uniform -1 1 1 1 1 0 1 Calculated multichoice acos({a}) = NAN? {=acos({a})}

log({b}) = -INF? {=log({b})}

1/{b} = INF? {=1.0/{b}}

]]> 1.0000000 0.3333333 0 0 1 abc 1 Your answer is correct. Your answer is partially correct. Your answer is incorrect. {=acos({a})} 0.1 1 2 2 {=log({b})} 0.1 1 2 2 {=1.0/{b}} 0.1 1 2 2 private a calculatedsimple uniform 1 2 1 1 1 1.1 1 private b calculatedsimple uniform -1 1 1 1 1 0 1